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Fix syntax errors

Ask Solem 16 yıl önce
ebeveyn
işleme
72ff807a4c
4 değiştirilmiş dosya ile 8 ekleme ve 5 silme
  1. 1 1
      README.rst
  2. 1 1
      celery/__init__.py
  3. 2 2
      celery/task.py
  4. 4 1
      celery/views.py

+ 1 - 1
README.rst

@@ -2,7 +2,7 @@
 celery - Distributed Task Queue for Django.
 ============================================
 
-:Version: 0.2.4
+:Version: 0.2.9
 
 Introduction
 ============

+ 1 - 1
celery/__init__.py

@@ -1,5 +1,5 @@
 """Distributed Task Queue for Django"""
-VERSION = (0, 2, 4)
+VERSION = (0, 2, 9)
 __version__ = ".".join(map(str, VERSION))
 __author__ = "Ask Solem"
 __contact__ = "askh@opera.com"

+ 2 - 2
celery/task.py

@@ -53,9 +53,9 @@ def apply_async(task, args, kwargs, routing_key=None, immediate=None,
         message_opts[option_name] = getattr(task, option_name, option_value)
 
     amqp_connection = DjangoAMQPConnection(connect_timeout=connect_timeout)
-    publisher = TaskPublsher(connection=amqp_connection)
+    publisher = TaskPublisher(connection=amqp_connection)
     task_id = publisher.delay_task(task.name, args, kwargs, **message_opts)
-    amqp_conection.close()
+    amqp_connection.close()
     return AsyncResult(task_id)
 
 

+ 4 - 1
celery/views.py

@@ -1,10 +1,13 @@
 """celery.views"""
 from django.http import Http404, HttpResponse
-from celery.task import is_done
+from celery.task import is_done, delay_task
 from celery.result import AsyncResult
 import simplejson
 
 
+def apply_async(request, task_name, *args, **kwargs):
+    res = delay_task(task_name, args, kwargs)
+
 def is_task_done(request, task_id):
     """Returns task execute status in JSON format."""
     response_data = {"task": {"id": task_id, "executed": is_done(task_id)}}